Richard Stevens asked: >I don't know if we have Chemists in the CH-Group, sorry I'm not just >experimental, but if so someone could calculate what will happen and what >will be the result if you mix equal parts of CH3COOH (vinegar) with >NaOH.... Na+ (aq) OH- (aq) + CH3COOH (aq) <------> Na+ (aq) + CH3CO2- + H20 (l) This is a classic Acid-Base Neutralization reaction. NaOH is a strong Base and Acetic acid (vinegar) is a weak acid. Its conjugate base CH3CO2- is a weak base. The result of mixing these to in aqueous solution in equal parts (1mol of each) will result in an aqueous salt and water. A small fraction of the acetate ions produced by the neutralization reaction will pick up protons from water and create a very small amount of OH-, which will give you a weakly basic solution. This reaction is quite reversible so an equilibrium will be reached. Testing for pH will tell you how far to go. Whew! This is a very interesting idea that someone is "bound" to try. You just gotta love chemistry. Robert Lusk.... www.PepperFool.com Recipes, Hot Sauce, Restaurant Reviews, Photos and more.